Please help
In Δ XYZ , side Z = 8, m < Y= 15* and m < Z = 94*. Find side y to the nearest tenth of an integer.

y = 2.1

Step-by-step explanation:

Considering the given triangle XYZ, to determine side y, we would apply the sine rule. It is expressed as

a/SinA = b/SinB = c/SinC

Where a, b and c are the length of each side of the triangle and angle A, Angle B and angle C are the corresponding angles of the triangle. Likening it to the given triangle, the expression becomes

x/SinX = y/SinY = z/SinZ

Therefore

y/Sin 15 = 8/Sin 94

Cross multiplying, it becomes

ySin94 = 8Sin15

0.998y = 8 × 0.259

0.998y = 2.072

y = 2.072/0.998

y = 2.1

2.1

Step-by-step explanation:

y/sinY = z/sinZ

y/sin(15) = 8/sin(94)

y = sin(15) × 8/sin(94)

y = 2.075608439

it is x equals 3   plese mark me really need it

step-by-step explanation:

his first public project he is asked to create a small scale drawing. the garden is a right triangle with base 25m and height 30m. are you trying to solve for the last side/hypotenuse? the irrational form of the answer would be 5\sqrt{61}