What is the equation of the circle with center (−13, −16) that passes through the point (−10, −16)? A) (x − 13)2 + (y − 16)2 = 9 B) (x + 13)2 + (y + 16)2 = 3 C) (x + 13)2 − (y + 16)2 = 9 D) (x + 13)2 + (y + 16)2 = 9

(x +13)² + (y +16)² = 9

Step-by-step explanation:

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equation of the circle

(x +13)² + (y +16)² = r²

now, (-10, -16) passes through the circle.

so, (-10+13)² + (-16 +16) =r²

r = 3

So, equation is

(x +13)² + (y +16)² = 9

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

the radius is 2 times the diameter.

step-by-step explanation: