What is an equation of the line that passes through the points (8,-3) and (8,4)

Step-by-step explanation:

Equation of a line

y = mx + c

Given two points

( 8 , -3) ( 8 , 4)

Step 1: find the slope

m = y2 - y1 / x2 -x1

( 8 , -3) ( 8 , 4)

x1 = 8

y1 = -3

x2 = 8

y2 = 4

Insert the values

m = 4 - (-3) / 8 - 8

= 4 + 3 / 0

= 7/ 0

Step 2: substitute any of the two points given into the equation

y = mx + c

( 8 , 4)

x = 8

y = 4

4 = 7/0 * 8 + c

c =

m can't be 7/0, that is math error which means that the points are not correct

no this is a nonlinear negative

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: