Designer Dolls, Inc. Found that the number N of dolls sold varies directly with their advertising budget A and inversely with the price P of each doll. The company sold 5200 dolls when $26,000 was spent on advertising and the price of a doll was set at $30. Determine the number of dolls sold when the amount spent on advertising is increased to $52,000 and the price of a doll is still $30. Round to the nearest whole number.

Given information:

Number of dolls =  N₁ = 5200

Advertising cost = A₁ = $26000

Advertising cost = A₂ = $52000

Cost of each doll = P = $30

Required Information:

Number of dolls =  N₂ = ?

Number of dolls = N₂ = 10400

Step-by-step explanation:

The number of dolls sold are directly proportional to the advertising expenses.

N ∝ A

The number of dolls sold are inversely proportional to the cost of each doll.

N ∝ 1/P

N = kA/P

Where k is the constant of proportionality.

Firstly, determine the constant k

k = PN₁/A₁

k = (30*5200)/26000

k ≈ 6

Now we can find the revised number of dolls at new advertising cost.

N₂ = kA₂/P

N₂ = (6*52000)/30

N₂ = 10400 dolls

As expected since the advertising cost and number of dolls were directly proportional, an increase in advertising cost  would cause increase in the number of dolls .

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.

7 ft 6 in means 7 1/2, because 6 in is 1/2 of a foot. 7 ft 8 in means 7 2/3 because 8 in is 2/3 of a foot. 23/3 = 7 2/3. 15/2 = 7 1/2.

23/3   *   15/2   = 57 1/2

step-by-step explanation: