The zoo increases the amount of food that the bear eats each week from 105 pounds to 115 pounds. What is the percent increase in the amount of food that the bear eats each week. Round your answer to the nearest tenth of a percent.

 The percent increase in the amount of food that the bear eats each week.= 9.5%

Step-by-step explanation:

Given : The zoo increases the amount of food that the bear eats each week from 105 pounds to 115 pounds.

i.e. Previous amount of food = 105 pounds

New amount of food = 115 pounds.

Increase in amount of food = (New amount of food )- (Previous amount of food)

= (115 pounds) - (105 pounds)

= 10 pounds

Now, the percent increase in the amount of food that the bear eats each week.=

Hence, the percent increase in the amount of food that the bear eats each week.= 9.5%

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.