Four times a number was 22 greater than twice the same number. What was the number?

11

Step-by-step explanation:

Set up an equation

Based on the question, we can determine that 4x = 22 + 2x where x in is the number

"Four times a number" -> 4x

"was" -> =

"22 greater than" -> 22 +

"twice the same number" -> 2x

Put the underlined parts together to get 4x = 22 + 2x

Solve equation

Rearrange/collect like terms to solve for x by subtracting 2x from both sides

4x = 22 + 2x

2x = 22

Solve for x by dividing each side by 2

2x = 22

x = 11

Final Answer

x = 11

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

1st part is 64,000,000

2nd part 500,000

step-by-step explanation: