At the district competition for 5th grade jump-roper of the year, the following number of jumps without stopping were recorded per student:203,245,237,233,90,100,100, 277,265,264,265,285,288,291,
291,290,300,224,200,257,290,279,266 ,288
what is the mean of the number of jumps

the mean of the number of jumps is 243 .

Step-by-step explanation:

Here we have , At the district competition for 5th grade jump-roper of the year, the following number of jumps without stopping were recorded per student:203,245,237,233,90,100,100,277,265,264,265,285,288,291, 291,290,300,224,200,257,290,279,266,288  . We need to find mean of the number of jumps . Let's find out:

We know that     where are the data and n is the number of data we have ! Now , according to question :

⇒ Mean = ( 203+245+237+233+90+100+100+277+265+264+265+285+288+291+

291+290+300+224+200+257+290+279+266+288 ) / ( 24 )

⇒

⇒

Therefore , the mean of the number of jumps is 243 .

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

jeff jeff

step-by-step explanation: