A pool measuring 10 meters by 26 meters is surrounded by a path of uniform width if the area of the pool and the path combined is 612 square meters what is the width of the path

the width of the path is 4 meters.

Step-by-step explanation:

Let x represent the width of the path.

A pool measuring 10 meters by 26 meters is surrounded by a path of uniform width. It means that the combined length of the pool and the path is (10 + 2x) meters.

Also, the combined width of the pool and the path is (26 + 2x) meters.

if the area of the pool and the path combined is 612 square meters, it means that

(10 + 2x)(26 + 2x) = 612

260 + 20x + 52x + 4x² = 612

4x² + 72x + 260 - 612 = 0

4x² + 72x - 352 = 0

Dividing through by 4, it becomes

x² + 18x - 88 = 0

x² + 22x - 4x - 88 = 0

x(x + 22) - 4(x + 22) = 0

x - 4 = 0 or x + 22 = 0

x = 4 or x = - 22

Since the width cannot be negative, then x = 4

4x and 6y

im not sure though

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.