If line A contains the points (3, -4) and (6, -2), and line B contains the points (-1, 5) and (1, 2), prove that the lines are perpendicular by multiplying their slopes.

Correct  sa · sb = 2/3 · (- 3/2) = - 1

Step-by-step explanation:

Given:

line A - (x₁, y₁) = (3, -4)   and (x₂, y₂) = (6, -2)

line B - (x₁, y₁) = (-1, 5)   and (x₂, y₂) = (1, 2)

The slope is calculated using the following formula:

s = (y₂ - y₁) / (x₂ - x₁)

sa = (-2 - (-4)) / (6 - 3) = (-2 + 4) / 3 = 2 / 3

sa = 2 / 3

sb = (2 - 5) / (1 - (-1)) = -3 / 2

when lines are perpendicular to each other then the slopes are in the next relationship:

sa · sb = - 1

we will check:

sa · sb = 2/3 · (- 3/2) = - 1

God is with you!!!

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.