The equation of the line which passes through the point (0,-3) and has a gradient of 1/2 is

y = 1/2x - 3

Step-by-step explanation:

So for this, I will be making the equation using the slope-intercept form, which is y=mx+b (m = slope, b = y-intercept). Putting everything together, our equation is y = 1/2x - 4.

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Given point ( 0 , -3 )

Gradient is another name for slope so Slope (m) = 1/2

The equation of line is given by

y - y1 = m ( x - x1)

y + 3 = 1/2 ( x - 0)

2 ( y + 3 ) = x

2y + 3 = x

x -2y - 3 = 0

which is the required equation of line

d

step-by-step explanation:

d