What is the equation of the line that passes through (5,1 with slope being -3?

A. Y+1=3x(x+5)
B. Y-1=3(x-5)
C. Y-1=-3(x-5)
D. Y+1=-3x(x-5)

Correct C

y = mx +c

m is the slope and c is the y-intercept

now, y = -3x +c (because slope is -3)

as the line passes through (5,1), these values must satisfy the above equation:

So, 1= -3 (5) + c

c= 1+ 15 =1 6

so, equation:

y = -3x +16

y = -3x +15 +1

y-1 = -3 (x -5)

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step-by-step explanation:

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation: