Does anyone know how to do this

7(x+2)(x+3)

Step-by-step explanation:

First, you want to find the GCF, 7 goes into all the terms evenly

so 7x^2 + 35x + 42 = 7(x^2 + 5 + 6)

to factor (x^2+5+6), you want to find two numbers whose product is 6 and whose sum is 5 (2 and 3)

so (x^2 + 5 + 6) becomes (x+2)(x+3)

and 7(x^2 + 5 + 6) becomes 7(x+2)(x+3)

Answer is 7(xsquared+5x+6)

Step by step:

all of the coefficients are divisible by seven so divide them y 7 and put 7 outside the parenthesis

answer: rolling a number cube and flipping a coin.

step-by-step explanation: