Scores of each of the previous calculus tests were normally distributed with a mean of 74 and standard deviation of 3.8. Steve will be taking the test tomorrow. What is the P(z<-1.05)?

-2.2 (-2.2124%)  is the answer as -2.2124^2 = -4.89% is found first below. -2.2124 is part of the derivation equation to find the relation with z.

z<-1.05 therefore = -2.2<-1.05

Step-by-step explanation:

-4.89%

-0.27631578947 x 74= -20.4473684208

P)z<-105) =  100/-20.4473684208 = -4.89060489067 less than the population of 100%

0 =population standard deviation = 3.8 we divide from 1.05

(in normal derivation questions we can multiply before dividing 0 key letter =(z- u)^2 / divide all by N) This is why we divided.

N=the size of the population = 100/D we used 100/D to find the first part.

z=each value from the population  = z<-1.05

u=the population mean = 74 we multiplied second step after first step 3.8 we divide from 1.05

So that 1.05/3.8 = -0.27631578947 x 74 = D

We then Divide into N = 100/D

to find a whole or a percentage.

= -4.89

z = -2.2

plants store their excess carbohydrate in the form of starch so that it could be used as energy source later on. the excess carbohydrate is converted into starch in the plastid i.e. chloroplast & this process occurs in the presence of sunlight. it is an insoluble polymer of glucose which gets stored in cell organelles named as amyloplasts. in some plants, starch is also stored in roots and embryos.

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94