What is the height of a rectangle
whose base is 40 inches and whose
diagonal is 41 inches?

You must draw a right triangle and label the hypotenuse as 41 and the longest leg (horizontal in this case, since we are to determine the height) as 40. We do not know the height so call it h.

Now the Pythagorean (sp /) Theorem states that the square of the hyp. is equal to the sum of the squares of the two legs.

so, 41 ^ 2 = 40 ^ 2 + h ^ 2

41 ^ 2 = 1681   40 ^ 2 = 1600     Therefore h ^2 must be equal to 81.   This means that h = 9.

The height is 9 inches.

Step-by-step explanation:

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~Alex

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation:

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