subject
Mathematics, 30.03.2020 01:08 lovely222

Suppose ABCD is a rhombus such that the angle bisector of ∠ABD meets
AD at point K. Prove that m∠AKB = 3m∠ABK. Help meee!! What do I put in the box shown below??


Suppose ABCD is a rhombus such that the angle bisector of ∠ABD meets  AD at point K. Prove that m∠AK

ansver
Answers: 1

Another question on Mathematics

question
Mathematics, 21.06.2019 18:00
If f(x) = 4x – 3 and g(x) = 8x + 2, find each function value a.f[g(3)] b.g[f(5)] c.g{f[g(-4)]}
Answers: 3
question
Mathematics, 21.06.2019 19:10
Which equation results from adding the equations in this system? x+6y=9 and -x+2y=-15
Answers: 1
question
Mathematics, 21.06.2019 23:00
72 the length of a side of a triangle is 36. a line parallel to that side divides the triangle into two parts of equal area. find the length of the segment determined by the points of intersection between the line and the other two sides of the triangle.
Answers: 1
question
Mathematics, 21.06.2019 23:50
Find the interior angle of a regular polygon which has 6 sides
Answers: 1
You know the right answer?
Suppose ABCD is a rhombus such that the angle bisector of ∠ABD meets
AD at point K. Prove tha...
Questions
question
Health, 20.10.2020 03:01
question
Arts, 20.10.2020 03:01
question
Mathematics, 20.10.2020 03:01
Questions on the website: 13722362