Please help with this

Step-by-step explanation:

Recall that cos Ф = adj / hyp.  If adj = 6 and hyp = 10, then by the Pythagorean Theorem, opp = 8:    6² + 8² = 10²

Then:

sin Ф = opp / hyp = 8/10 or 4/5

cos Ф is given:         6/10 or 3/5

tan Ф = opp / adj:      8/ 6 or 4/3

cot Ф   = 1/sin Ф = 10/8 or 5/4

sec Ф  = 1/ cosФ  =  10/6 or 5/3

csc Ф  = 1 / sin Ф = 10/8 or 5/4

idk the answer but just put a

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.