Cesium-137 is a particularly dangerous by-product of nuclear reactors. It has a half-life of 30 years. It can be readily absorbed into the food chain. Suppose we place 3,000 grams of
cesium-137 in a nuclear waste site.
(a) How much cesium-137 will be present after 30 years, or one half-life?
9
How much cesium-17 will be present after 60 years, or two half-lives?
(b) Find an exponential formula that gives the amount G in grams of cesium-137 remaining in the site after h half-lives.
(c) How many half-lives of cesium-137 is 250 years? Round your answer to two decimal places.
half-lives
(d) Use your answer to part (c) to determine how much cesium-137 will be present after 250 years. Round your answer to the nearest whole number

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

the answer is a.

135 and 80

step-by-step explanation: