My geometric sequence is 16,-3.2,0.64,-0.128..what is the 7th term

Step-by-step explanation:

In a geometric sequence, the nth term is

T_n = ar^(n-1)

a = first term

r = common ratio which can be gotten by dividing second term by first term, third term by second term etc

Therefore

a = 16

r = -3.2 ÷ 16

r = -0.2

T_7 = ar^(7-1)

T_7 = ar^6

T_7 = 16[(-0.2)^6]

T_7 = 16(0.000064)

T_7 = 0.001024

2*2=3

two times two is four

i dont understand what you mean so pls comment

-3(b-8)-5=9(b+2)+1

distribute

-3b+24-5=9b+18+1

add/ subtract

-3b+20=9b+19

20-19= 1

-3b+1=9b

9b+3b= 12b

1=12b

1 divided by 12 = 1/12

answer: 1/12 = b