Solving Quadratic Equations by Completing the Square
Warm-Up
What are the two solutions of the equation?
x= v5 and x = -5
Solve the quadratic equation by completing the square.
0 = x2 - 6x + 4
4 = x2 - 6x
- 4 + 9 = (2x2 - 6x +9)
5=(x-3)2
x = 3 + v5 and x = 3 - 5
x = 5+ ε and x = 5 -
x=
E and x = -
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answer: i can’t tell you that

step-by-step explanation:

noncoplanar points are points that do not lie on the same line.

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9