On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom. The locust population gains 6/7 of its size every 2.4 days, and can be modeled by a function, L, which depends on the amount of time, t (in days). Before the first day of spring, there were 4600 locusts in the population. Write a function that models the locust population t days since the first day of spring.

4600*(13/7)^t/2.4.

Step-by-step explanation:

We already know that it starts with 4600 locusts. You may think we just do: 4600*6/7. But notice they said: "Of it's size" So it would actually be; 4600+4600*6/7. We can take out a 4600 to make it: 4600(1+6/7). 1 AKA 7/7+6/7 is 13/7. Now we have: 4600*13/7. The problem also says:" Every 2.4 days". Lastly, we add an exponent to 13/7 as t/2.4 days. Our final answer is 4600*(13/7)^t/2.4.

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify