Sara is wrapping a gift box with dimensions 10 inches by 14 inches by 5 inches with wrapping paper. What is the least amount of wrapping paper she will need to cover the gift box without any overlap?

520 square inches

Step-by-step explanation:

To do this we just have to find the surface area of the box

The formula would be

SA=2lw+2lh+2wh

so we can assign these dimensions to a value

l: 10

w: 14

h: 5

and plug our values in

SA=2(10)(14)+2(10)(5)+2(14)(5)

and simplify

SA=2(140)+2(50)+2(70)

SA=280+100+140

SA= 520

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

c

step-by-step explanation: