) Suppose that an urn contains 7 green, 8 red, and 9 yellow balls. You pick a ball at random and replace it. You then do this 9 more times (making 10 times altogether). What is the probability that you selected green 2 times, red 3 times, and yellow 5 times?

Title:

Step-by-step explanation:

In the urn, there are total (7 + 8 + 9) = 24 balls.

We are taking 10 balls out of the urn with replacement.

In each tern, we have overall 10 choices to chose 1 ball.

If we want to get a green, there are 7 choices each time.

Similarly, 8 choices each time for getting a red and 9 choices each time for getting a yellow ball.

The probability of getting green 2 times, red 3 times, and yellow 5 times is .

45

step-by-step explanation:

smple

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: