Solve for x
-1(-3x^2+2x+8)=1(0)

x= -4/3 or x = 2

Step-by-step explanation:

If this is the correct form of the question, let's get done with it easily.

We'll pay keen attention to their signs.

-1 (-3x² + 2x + 8 ) = 1(0)

First, we open the bracket using (-1) to Multiply through.

3x² - 2x - 8 = 0

Sum of roots of the equation = -2

Products of the equation = -24

The roots of the equation would be:

(-6x , 4x). The EQUATION becomes:

3x² - 2x - 8 = 0

3x² - 6x + 4x - 8 = 0

3x ( x - 2) + 4( x - 2) = 0

(3x + 4) (x - 2) = 0

3x + 4 = 0. OR x - 2 = 0

3x = - 4. x = 2

x = -4/3

Therefore, x = -4/3 or 2

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation: