1 point) It is easy to check that for any value of c, the function y=x2+cx2 is solution of equation xy′+2y=4x2, (x>0). Find the value of c for which the solution satisfies the initial condition y(10)=2.

c=-0.98

Step-by-step explanation:

We know that the function

is solution of the differential equation

to find the value of c we use the condition y(10)=2

then, c = -0.98

hope this helps!!

darn right!

step-by-step explanation:

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step-by-step explanation: