A research company desires to know the mean consumption of milk per week among males over age 45. They believe that the milk consumption has a mean of 4.5 liters, and want to construct a 95% confidence interval with a maximum error of 0.08 liters. Assuming a variance of 1 liters, what is the minimum number of males over age 45 they must include in their sample? Round your answer up to the next integer.

The minimum number of males over age 45 they must include in their sample is 601

Step-by-step explanation:

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

So it is z with a pvalue of , so

Now, find the margin of error M as such

In which is the standard deviation of the population(square root of the variance) and n is the size of the sample.

Assuming a variance of 1 liters, what is the minimum number of males over age 45 they must include in their sample?

This is n when

Rounding up

The minimum number of males over age 45 they must include in their sample is 601

i think the amount would be $140.62