A fast food restaurant executive wishes to know how many fast food meals adults eat each week. They want to construct a 85% confidence interval with an error of no more than 0.08. A consultant has informed them that a previous study found the mean to be 5.6 fast food meals per week and found the standard deviation to be 1.3. What is the minimum sample size required to create the specified confidence interval? Round your answer up to the next integer.

The sample size must be 548 to have a margin of error of no more than 0.08.

Step-by-step explanation:

We are given the following in the question:

Sample mean = 5.6

Standard deviation = 1.3

Significance level = 15%

Margin of error = 0.08

We have to estimate the sample size.

Margin of error =

Putting values, we get

Thus, the sample size must be 548 to have a margin of error of no more than 0.08.

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.