A cube with 25-cm-long sides is sitting on the bottom of an aquarium in which the water is one meter deep. (Round your answers to the nearest whole number. Use 9.8 m/s2 for the acceleration due to gravity. Recall that the weight density of water is 1000 kg/m3.)
a. Estimate the hydrostatic force on the top of the cube.
b. Estimate the hydrostatic force on one of the side of the cubes.

Hydro static force on the top of the cube F = 613.125 N

Hydro static force on one side of the cube F = 766.4 N

Step-by-step explanation:

Side of the cube = 25 cm = 0.25 m

Depth of water h = 1 m

(a). Hydro static force on the top of the cube

Hydro static pressure is given by P = g h

Put all the values in above formula we get

P = 1000 × 9.81 × 1

P = 9810 Pa

Now hydro static force F = Hydro static pressure × Area

F = 9810 ×

F = 613.125 N

(b). Hydro static force on one side of the cube

Hydro static pressure on one side of the cube is given by P = g (h + 0.25)

P = 1000 × 9.81 × (1 + 0.25)

P = 12262.5 Pa

Now hydro static force F = Hydro static pressure × Area

F = 12262.5 ×

F = 766.4 N

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