Is (4, 1) a solution to this system of inequalities?

x ≥ 4
x + 7y ≤ 11

Explanation:

Plug (x,y) = (4,1) into the first inequality

We replace x with 4. There is no y value to worry about here.

After doing so, x ≥ 4 turns into 4 ≥ 4 which is a true statement.

Plug (x,y) = (4,1) into the second inequality

x + 7y ≤ 11 turns into 4 + 7(1) ≤ 11 which simplifies to 11 ≤ 11

This is also a true statement.

Both inequalities result in true statements after plugging in (x,y) = (4,1). Therefore, (4,1) is a solution.

step-by-step explanation: