A university's administrator proposes to do an analysis of the proportion of graduates who have not found employment in their major field one year after graduation. In previous years, the percentage averaged 15%. He wants the margin of error to be within 5% at a 99% confidence level. What sample size will suffice? Round to the nearest integer.

339

Step-by-step explanation:

We have that the formula would come being:

n = p (1-p) * [z (α / 2) / B] ^ 2

let p, percentage averaged (0.15)

B = 5%, 0.05 (bottom margin)

α = 1 - A

A, top margin 99%

α = 1 - 0.99 = 0.01

α / 2 = 0.005

z (0.005) = 2.58 (attached normal distribution table), the value is negative in the table but is taken as positive.

Replacing we have:

n = 0.15 * (1 - 0.15) * [2.58 / 0.05] ^ 2

n = 0.1275 * (2.58 / 0.05) ^ 2

n = 339.4764

Therefore the sample size is 339.

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

the ratio of balloons to tables is 5: 2 and the constant variation is 5.

the equation is y=5x