PLEASE ASAP HELP :(
Compare Accounts A and B. Then complete the sentences.

There are two rectangles. The first rectangle with heading Account A and content principal: $16,000; annual interest: 3%, compound quarterly number of years: 10 and the second rectangle with heading Account B and content principal: $16,000; annual interest: 3%, compound monthly number of years: 10.

Account

is worth the most after 10 years. It will have a value of $

.

Account B is worth the most after 10 years. It will have a value of $21591

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

Considering account A,

P = $16000

r = 3% = 3/100 = 0.03

n = 4 because it was compounded 3 times in a year and n = 12/3 = 4

t = 10 years

Therefore,

A = 16000(1 + 0.03/4)^4 × 10

A = 16000(1 + 0.0075)^40

A = 16000(1.0075)^40

A = $21574

Considering account B,

P = $16000

r = 3% = 3/100 = 0.03

n = 12 because it was compounded 12 times in a year.

t = 10 years

Therefore,

A = 16000(1 + 0.03/12)^12 × 10

A = 16000(1 + 0.0025)^120

A = 16000(1.0025)^120

A = $21591

Therefore,

Account B is worth the most after 10 years. It will have a value of $21591

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,