Solve and check the following system:
X +2y =4
2x - y =3

Step-by-step explanation:

To solve this system of equation, let's multiply the second equation by two so both equations have a :

Next, let's add the two equations together to remove the and solve for :

Now that we have the value of , we can plug it into either of the equations to solve for :

or

Therefore, the solution to this system of equations is .

The solution of the given system of equation is x = 2 and y = 1

Step-by-step explanation:

Given,

x+2y = 4 eq 1

2x -y = 3 eq 2

To find the value of x and y

Putting y = 2x-3 from eq 2 in eq 1 we get,

x+2(2x-3) = 4

or, x+4x-6 = 4

or, 5x = 10

or, x = 2

Again,

From eq 2 we get,

y = 2×2-3 = 1

Hence,

x = 2 and y = 1

Checking:

Putting the values of x=2 and y=1 in eq 1 and eq 2 we get,

2 + 2×1 = 4 and

2×2-1 = 3

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)