Mathematics, 31.03.2020 07:55 peno211
The teacher drew a rectangle the width of which was 11 inches shorter than the length. Then, he increased both the width and the length such that the area of the new rectangle was w^2+22w+72 inches, where w was the width of the first rectangle. How much were the width and the length increased?
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The teacher drew a rectangle the width of which was 11 inches shorter than the length. Then, he incr...
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