Mathematics, 31.03.2020 13:07 caromaybelline71

The small cylinder can fill
the big cylinder to a height
of 5 cm.
Work out the radius
of the big cylinder.

The small cylinder can fill the big cylinder to a height of 5 cm. Work out the radius of the big cyl

Answers: 1

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Answer from: kimberlylove387

The radius of the big cylinder is 5.857 cm and this can be determined by using the formula of volume of the cylinder.

Given :

The small cylinder can fill the big cylinder to a height of 5 cm.The diameter of the small cylinder is 7cm and the height of the small cylinder is 14cm.

First, find the volume of the small cylinder. The volume of the cylinder is given by the formula:

$\rm Volume = \pi r^2h$

where 'r' is the radius of the cylinder and 'h' is the height of the cylinder.

Now, substitute the values of the radius 'r' and height 'h' of the small cylinder in the above formula.

$\rm V = \pi \times (3.5)^2\times (14)$

$\rm V = 171.5\pi$

Now, it is given that the small cylinder can fill the big cylinder to a height of 5 cm that is:

$171.5\pi = \pi \times r^2 \times (5)$

$171.5=r^2 \times 5$

$\sqrt{34.3} = r$

r = 5.857 cm

For more information, refer to the link given below:

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Answer from: Happypuppy1918

5.857 cm

Step-by-step explanation:

A cylinder's volume is given by the formula:

$V=\pi r^2h$

-The small cylinder's dimensions are d=7, h=14, it's volume is calculated as:

$V=\pi r^2h\\\\=\pi \times (7/2)^2\times 14\\\\=171.5\pi$

We are told that this volume fills the big cylinder to a height of 5cm.

#We equate this volume to the big cylinder's 5cm and solve for r:

$V=\pi r^2h\\\\171.5\pi=\pi r^2\times 5\\\\171.5=5r^2\\\\r=\sqrt{171.5/5}\\\\=5.857 \ cm$

Hence, the radius of the big cylinder is 5.857 cm

Answer from: Quest

step-by-step explanation:

Answer from: Quest

see below

step-by-step explanation:

7. there are 10 data points in the set. the middle point is between 5 and 6. the middle point in the top half is 8 and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term point 8 = 100 point 3 = 88

iqr = 100-88 = 12

final point 8 = 93 point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6. b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical . there is an outlier for the males that skews the data

5. the iqr is a better measure of spread for the movies and basketball games. since the basketball game has an outlier, we do not want to use standard deviation for measurement.

3. the exam median is much higher than the class median. the median line is farther to the right on the exams

2. there is no way to tell what the means are from the box and whisker plots.

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