The sound intensity of a whisper is times the reference intensity.

333.3 times

Step-by-step explanation:

Given : The function  gives the intensity of a sound in decibels, where x is the ratio of the intensity of the sound to a reference intensity.

A whisper has a sound intensity of 30 decibels.

To find : Use your graph to help you complete the following statement. The sound intensity of a whisper is times the reference intensity.

Solution : Graph is attached which shows their intersection at (1000,30).

We can also verify by substituting value.

We have given that a whisper has a sound intensity of 30 decibels.

Therefore, y=30 , Let log base 10

y = 10logx

30 = 10logx                              

\frac{30}{10} =logx

3=logx

Logarithmic property log_{x}b=a \ RIGHTARROW b=x^a

x=10^3

x=1000

The ratio of the intensity of the sound to a reference intensity is 1000 decibels. The sound intensity of a whisper is times the reference intensity is. The sound intensity of a whisper is 333.3 times the reference intensity.

1000

Step-by-step explanation:

just took the test ur welcome

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation:

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