Determine the equation of a circle with a center at (-4,0) What is the equation of a circle with a center at (-4, 0)
that passes through the point (-2, 1) by following the that passes through the point (-2, 1)?
steps below.
O x2 + (y + 4)2 = 15
1. Use the distance formula to determine the radius:
d = (x2-x;)+ V2 -V,).
O (x – 1)2 + (y + 2)2 = 5
O (x + 4)2 + y2 = 5
2. Substitute the known values into the standard form:
(x – h) + (y – k)? = ?.
O (x + 2)2 + (y – 1)2 = 5
Intro
Done
(x+4)2 + y2 = 5

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

536

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )