What is the vertex of the graph of y=x^2+4x

Vertex is at  

( 2 , − 4 )

Step-by-step explanation:

x v e r t e x = − b 2 a ; y v e r t e x = f ( − b 2 a )  given the equation in the standard form of

a x 2 + b x + c

Given : y = x 2 − 4 x + 0a = 1 , b = − 4 , c = 0

x v e r t e x = − ( − 4 ) 2 ⋅ 1 =4 2 = 2

y v e r t e x = f ( 2 ) = ( 2 ) 2 − 4 ( 2 ) = 4 − 8 = − 4

Vertex :  ( x , y ) = ( 2 , − 4 )

graph{x^2-4x [-6.43, 7.62, -5.635, 1.39]}

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29