Can you please solve this problem

(-1, -6)

Step-by-step explanation:

First, make sure each equation follows this format:

y = mx + b

Where m is the slope and b is the y-intercept

Equations:

y = 6x

2x + 3y = -20

The equation in bold is not formatted correctly. Let's make it into the slope-intercept form (y = mx + b).

Subtract 2x on both sides:

2x + 3y = -20

-2x           -2x

3y = -2x - 20

Divide by 3 on both sides:

3y = -2x - 20

/3     /3    /3

y = -2/3x -20/3

Now, we have our two equations!

y = 6x

y = -2/3x -20/3

To solve, we need to use substitution. Therefore, set the equations equal to themselves.

y = 6x

y = -2/3x -20/3

6x = -2/3x -20/3

Solve:

6x = -2/3x -20/3

Add 2/3x on both sides:

6x = -2/3x -20/3

+2/3x        +2/3x

6 2/3x = -20/3

Divide by 6 2/3 on both sides:

6 2/3x = -20/3

/6 2/3     /6 2/3

x = -1

Therefore, the x-coordinate of the interception point between these two lines is -1.

To find the y-coordinate, substitute the value of x into one of the equations. Let's use y = 6x.

Substitute:

y = 6x

y = 6(-1)

Multiply:

y = 6(-1)

y = -6

Therefore, the y-coordinate of the interception point between these two lines is -6.

The ordered pair is (-1, 6). This means that the two lines have one solution, or one place where they intersect. That location is (-1, 6).

4 and 5)16.97 or 12√2

6)15.59 or 9√3

7)y = 15.59 or 9√3     x =27

8)17.80

what are you trying to solve here

step-by-step explanation: