A sample of 20 silver dollar coins is weighed. The mean of the sample is 8.0710 g and the standard deviation of the sample is 0.0411 g. Construct a 95% confidence interval estimate of the mean weight of all the coins.
8.0447 g < μ < 8.0973 g

8.0329 g < μ < 8.1121 g

8.0518 g < μ < 8.0902 g

7.6675 g < μ < 8.4746 g

c

step-by-step explanation:

p

step-by-step explanation:

answer: 5 17/33 % (to the tenth)

step-by-step explanation:

he guessed: 34.5 pounds

actual weight is 32.7

there for he is off:

34.5 -32.7 = 1.8

32.7 is the 100%

1.8 represents %? of 32.7

therefore:

32.7   - 100%

1.8     -     x%

x= 1.8*100%/32.7% = 18*100%/327%

x=1800%/327%   = (5 165/327)%

to the tenth:

5 17/33 %