Write an equation in slope intercept of the line passing through point A(1,2) and parallel to line B given equation y=3x-5

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be parallel, they have to have the same slope.

y = 3x - 5     m = 3

The given line's slope is 3, so the parallel line's slope is also 3. Plug this into the equation:

y = mx + b

y = 3x + b     To find b, plug in the point (1, 2) into the equation

2 = 3(1) + b

2 = 3 + b     Subtract 3 on both sides to get "b" by itself

2 - 3 = 3 - 3 + b

-1 = b

y = 3x - 1

answer: you need to organize this better it does not make sense.

step-by-step explanation: ?