Two sets of 4 consecutive positive integers have exactly one integer in commonThe sum of the integers in the set with greater numbers is how much greater than the sum of the integers in the other set?

A4
B7
C8
D12
Eit cannot be determined from the information given.

D.12

Step-by-step explanation:

The first thing is to determine the two integer sets, which we will start with the number 1, therefore the first would be:

{1,2,3,4}

We know that it has a number in common, which in this case would have to be 4, therefore, the other set would be:

{4,5,6,7}

Therefore the sets are:

{1,2,3,4}; {4,5,6,7}

Now to calculate the difference between the sum of the integer between them it would be:

(5 - 3) + (6 - 2) + (7 - 1)

= 2 + 4 + 6

= 12

The answer then would be D.12

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step-by-step explanation:

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.