If 10-mm-wide snowflakes shaped like regular hexagons were to tile a 40 mm wide by 30 mm tall area, how many snowflakes would there be?

i don't even know man. edge inuity be messing with us. i had to ask a question too.

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

f(x)=2/3x+4/3 is the answer because is whose power in the senate is equal to the power of the speaker of the house?

step-by-step explanation:

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.