Which statement is true about the equations -3x + 4y = 12 and 1x - 3y = 1?
The system of the equations has exactly one solution at (-8, 3).
The system of the equations has exactly one solution at (-4, 3).
The system of the equations has no solution the two lines are parallel
The system of the equations has an infinite number of solutions represented by either equation

one solution at (-8,-3)

Step-by-step explanation:

-3x + 4y = 12

1x - 3y = 1

Multiply the second equation by 3

3(1x -3y ) = 1*3

3x -9y =3

Add this to the first equation

-3x+4y = 12

3x-9y =3

-5y = 15

Divide each side by -5

-5y/-5 = 15/-5

y =-3

Now solve for x

x -3y =1

x -3(-3) =1

x+9 =1

Subtract 9 from each side

x+9-9=1-9

x=-8

(-8,-3)

One solution: (-8,-3)

The system of the equations has exactly one solution at (-8, -3)

Step-by-step explanation:

-3x + 4y = 12

x - 3y = 1

x = 1 + 3y

-3(1 + 3y) + 4y = 12

-3 - 9y + 4y = 12

-5y = 15

y = -3

x = 1 + 3(-3) = -8

One solution: (-8,-3)

answer: the four apples you took away.

step-by-step explanation:

the ratios are reciprocals im positive

step-by-step explanation:

they are all positive numbers so it wouldn't be the other ones