Filipo is building a rectangular sandbox . The length of the sandbox is 1 foot longer than twice the width of the sandbox .the perimeter of the sandbox is 29 feet

Which equation could be used to determine w ,the width, in feet of the sand box?

A.) w + w + 2 = 29

B.) w + 2w + 1 = 29

C.) 2w + 2(w + 2) = 29

D.) 2w + 2(2w+ 1) = 29

Part B what is the length in feet of the sandbox

Part A : D.)

Part B : Length of the sandbox is 10 feet.

Step-by-step explanation:

Given,

Perimeter = 29 ft

We need to find the equation for the perimeter and also the length of the sandbox.

Solution,

Let the width of the sandbox be 'w'.

Now as per question said;

The length of the sandbox is 1 foot longer than twice the width of the sandbox.

So we can say that;

Length =

Now we know that the perimeter is equal to the sum of twice of length and width.

framing in equation form, we get;

Perimeter =

we have given the perimeter, so on substituting the value, we get;

Hence The equation used to find the width is  .

Now we solve for 'w'.

Applying distributive property, we get;

Subtracting both side by '2' we get

Dividing both side by 6 we get;

Width of the sandbox = 4.5 ft

Length of the sandbox =

Hence Length of the sandbox is 10 feet.

Part A : D

Part B : Length of the sandbox is 10 feet amd the width is 4.5 feet.

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680