Suppose y varies directly with x. Write a direct variation equation that relates x and y. Then find the value of y when x=10.

y=6 when x=5
Write a direct variation equation that relates x and y.
y=

y = 12

Step-by-step explanation:

from the question,

y varied directly with x .

mathematicaly  

y ∝ x

y = kx  where k is constant of proportionality

k = y/x

to find k, given that  y = 6 , x = 5

so,

k = 6/5

k = 1.2

inorder to find the value of y when x = 10

from y = kx

y = 1.2 x 10

y = 12

also,

the  direct variation equation that relates x and y is

y = kx direct variation equation that relates x and y

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: