Which factorization is incorrect? 1) x3 + 5x2 + 4x + x2 + 5x + 4 = (x + 4)(x + 1)2 2) 4d3 – 4d2 – 9d + 9 = (d – 1)(2d – 3)2 3) 27h3 – 8k3 = (3h – 2k)(9h2 + 6hk + 4k2 ) 4) 64 – 9t2 = (8 + 3t)(8 – 3t)

The second option is the incorrect:

2) 4d3 – 4d2 – 9d + 9 = (d – 1)(2d – 3)^2

Step-by-step explanation:

Let's check each one of the factorizations:

1) x3 + 5x2 + 4x + x2 + 5x + 4 = (x + 4)(x + 1)^2

(x + 4)(x + 1)^2 = (x + 4)(x2 + 2x + 1) = x3 + 6x2 + 9x + 4

x3 + 5x2 + 4x + x2 + 5x + 4 = x3 + 6x2 + 9x + 4

This one is correct.

2) 4d3 – 4d2 – 9d + 9 = (d – 1)(2d – 3)^2

(d – 1)(2d – 3)^2 = (d - 1)(4d2 - 12d + 9) = 4d3 - 16d2 + 21d - 9

4d3 – 4d2 – 9d + 9 = 4d3 - 16d2 + 21d - 9

This one is incorrect.

3) 27h3 – 8k3 = (3h – 2k)(9h2 + 6hk + 4k2 )

(3h – 2k)(9h2 + 6hk + 4k2 ) = 27h3 - 8k3

This one is correct.

4) 64 – 9t2 = (8 + 3t)(8 – 3t)

(8 + 3t)(8 – 3t) = 64 - 9t2

This one is correct.

So the incorrect option is the second one.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

answer would be 8.64 or s = 11π/4 inches

step-by-step explanation:

s = r θ  

where s = arc length  

r = radius = 3 inches  

θ = central angle in radians = ( π /180)*165  

s = 3(π/180)*165  

= 8.64 inches