What is the solution of log2x + 727 = 3? (little 2x and little 7 before the 27)
a. x=-2
b. x=2
c. x=3
d. x=4

Remember
means
y is the power to which n must be raised to obtain x
aka
n^y=x

also
if a^n=b^n where n=n, then a=b


translate
(2x+7)^3=27
see if we can match the bases
(2x+7)^3=3^3
therefor
2x+7=3
minus 7 
2x=-4
divide 2
x=-2