A table mat has a perimeter of 32 inches The width of the table mat is triple it’s length write equation find the length and width then write the area of the table mat

Length of mat = 4 inches

Width of mat = 12 inches

Area of table mat = 48 square inches

Step-by-step explanation:

Given

Perimeter = P = 32

Let l be the length of the table mat and w be the width of table mat

According to given statement

The perimeter of a rectangular object is given by:

Putting w=3l and value of P

Dividing both sides by 8

So

Length = l = 4 inches

And

Width = 3l = 3*4 = 12

Now

Hence,

Length of mat = 4 inches

Width of mat = 12 inches

Area of table mat = 48 square inches

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²