Rectangle j'k'l'm' shown on the grid is the image of rectangle jklm after transformation. the same transformation will be applied on trapezoid stuv.

what will be the location of t' in the image trapezoid s't'u'v'?

The coordinates of T' will be T'(13,-1)

Step-by-step explanation:

step 1

Find the rule of the translation

take any point of rectangle JKLM (pre-image)

The coordinate of point k(-3,2)

The coordinate of point k'(4,7)

so

The rule of the transformation

k(-3,2) > k'(4,7)

is equal to

(x,y) > (x+7,y+5)

That means > the translation is 7 units at right and 5 units up

step 2

Apply the rule of the translation at the coordinate T of trapezoid STUV

we have

T(6,-6)

(x,y) > (x+7,y+5)

T(6,-6) > T'(6+7,-6+5)

T(6,-6) > T'(13,-1)

therefore

The coordinates of T' will be T'(13,-1)

domain is all the x values included in the

0 ≤ x ≤ 2

range is all the y values of the graph

-2 ≤ y ≤ 2

***keep in mind that there are different ways to show domain and range

hope this !

~just a girl in love with shawn mendes

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step-by-step explanation:

i used the pitagoras theoreme