A rectangular garden is fenced on three sides with a wall forming on the fourth side. The total length of the fence is 120m. The area of the garden is 1600m^2. Find the dimensions of the garden.

20m by 80m

Step-by-step explanation:

Let the dimension of the garden be x by y

The garden is fenced on three sides with a perimeter of 120m

Perimeter of the three sides = 2x+y

Therefore:

The Area of the garden =

From the first equation, y=120-2x

Substitute  y=120-2x into xy=1600

xy=1600

x(120-2x)=1600

Recall,

xy=1600

When x=20, 20y=1600===>y=80

When x=40, 40y=1600===>y=40

So we have the pair (20,80) and (40,40).

However since we are told that the garden is rectangular, we pick the dimension with unequal sides.

The dimension of the garden is 20m by 80m.

536

step-by-step explanation:

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40