At a certain time instant, the vector → a ( t ) a→(t) has → a = − ^ ı + 4 ^ ȷ m ˙ → a = ^ ı + ^ ȷ m / s . a→=−ı^+4ȷ^ ma→˙=ı^+ȷ^ m/s. matlab/mathematica input: avec = [-1,4] adotvec = [1,1] at this same instant of time, what is d d t ∥ proj ( → a ( t ) , ^ a ( t ) ) ∥ ddt‖proj⁡(a→(t),a^(t))‖?

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

add an image, and i will answer

step-by-step explanation:

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step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)